Mixture Problem

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How many cubic centimeters of pure hydrochloric acid should be added to 20 cc of a 30% solution of hydrochloric acid to obtain a 50% solution?

 Let x = number of cc of pure acid. One can set up a table as below. In particular, you start with 20 cc (cubic centimeters = volume) of a 30% solution of acid. This means that 20(.30) = 6 cc is acid and the rest is water. If you add x cc of pure acid, then you have a new total volume of 20+x cc with 6+x cc of it acid. Thus, for it to be 50% of the total, one needs that (20+x)(.50) = 6+x cc of it acid. Solving for x, you should get x = 8 cc.
 
 

Volume (cc)

Concentration
(%)
Amt of Pure Acid (cc)
 = Volume X Concentration
Pure Acid x 100 x
30% Solution 20 30 20(.30) = 6
50% Solution 20+x 50 (20+x)(.50)

The below figure shows how one might visualize the relationship between the volume and concentration (percent of total volume) for putting a substance (acid) in water. Of course, the colors and separation of the acid and water are exaggerations in order to make a point. These mixtures are typically well mixed and are often colorless.

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E-Mail: Dr. Russell Herman Last Updated: August 27, 2004