Essential Trigonometry
The Greek words trigonon, meaning triangle, and metria, meaning measurement, are combined to form the word trigonometry. Trigonometry was simply the study of the sides and angles of the triangle together with applications to navigation, surveying, and astronomy. Trigonometry has evolved into a very powerful analytical tool when combined with the calculus.


| Fig. III a. | Fig. III b. |
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sin q = y/r |
cos q = x/r |
tan q = y/x |
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csc q = r/y |
sec q = r/x |
cot q = x/y |
In the special case where r = 1
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sin q = y |
cos q = x |
tan q = sin q / cos q |
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csc q = 1/ sin q |
sec q =1/cos q |
cot q = cos q / sin q = 1/ tan q |
Special triangle where
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sin q = 1 / |
cos q = 1/![]() |
tan q = 1 |
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csc q =![]() |
sec q =![]() |
cot q = 1 |
Special triangle where
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sin q = 1 / 2 |
cos q = / 2 |
tan q = 1 /![]() |
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csc q = 2 |
sec q =2 /![]() |
cot q =![]() |
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Pythagorean Identities (divide the first by cos2 q to obtain the second, by sin2 q to obtain the third) |
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sin2 q + cos2 q = 1 |
tan2 q + 1 = sec2 q |
1 + cot2 q = csc2 q |
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Complementary Angle Identities |
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sin( p /2 - q ) = cos q |
cos( p /2 - q ) = sin q |
tan( p /2 - q ) = cot q |
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Supplementary Angle Identities (consider the points (x, y), (-x, y), (-x, -y), (x, -y) ) |
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sin( p - q ) = sin q , sin(p + q ) = -sin q |
cos( p + q ) = -cos q |
tan( p + q ) = tan q |
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Addition Identities |
Subtraction Identities |
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sin( a + b ) = sin a cos b + cos a sin b |
sin( a - b ) = sin a cos b - cos a sin b |
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cos( a + b ) = cos a cos b - sin a sin b |
cos( a - b ) = cos a cos b + sin a sin b |
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tan( a + b ) = (tan a + tan b ) / (1 - tan a tan b ) |
tan( a - b ) = (tan a - tan b ) / (1 + tan a tan b ) |
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The angle between two lines: |
tan q = (m2 -m1) / (1 + m2m1) |
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Double Angle Identities (let b = a in the addition identities) |
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sin(2 q ) = 2 sin q cos q |
cos(2 q ) = cos2 q - sin2 q |
tan(2 q ) = 2 tan q /(1 - tan2 q ) |
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Pythagorean Identity gives: |
cos(2 q ) = 2cos2 q - 1 |
cos(2 q ) = 1 - 2sin2 q |
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Half-angle Identities |
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sin2( q /2 ) = (1 - cos q ) / 2 |
cos2( q /2 ) = (1 + cos q ) / 2 |

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Find q if sin q = |
We begin by looking for positive angles that satisfy the equation. Because sin q is positive, the angle q must terminate in either the first or second quadrant. Our knowledge of special triangles tells us that this angle may be either p /3 or 2p /3.Our solutions are q = p /3 + 2np , n = 0, 1, 2, … and q = 2p /3 + 2np , n = 0, 1, 2, … |
To define an inverse trigonometric function one must restrict the domain of the function so that it is one-to-one. For the sine and tangent functions this is typically -
p /2 to p /2. For the cosine function this is 0 to p . However for the secant function, the range is not standardized. Varberg and Varberg use 0 to p , q ¹ p /2, in order to take advantage of the relationship
VIII. Graphs of the Trigonometric functions and their Inverses