1. Given the recurrence ak
= -ak - 1
+ 12ak - 2, a0 = 1, a1
= 8.
- Write out the next three terms of this
sequence.
4, 92, -44
- What is the characteristic equation?
t2 + t - 12 = 0
- Given the roots to the characteristic
equation are r = 3 and s = -4, write an equation for an
based on the linear combination of the roots to this characteristic
equation using real constants C and D.
an = C(3)n
+ D (-4)n.
- Use the initial conditions to solve
for the constants C and D and write an explicit formula for the recurrence
relation.
a0 = C(3)0 + D
(-4)0 = 1 ®
C = 1 - D, a1 = (1 - D )(3)1 + D (-4)1
= 8 ® D = (8 - 3)/(-4 - 3) =
5/(-7) = -.714285714286,
C = 1 - D = 1 + 5/7 = 12/7 = 1.71428571429.
an = (12/7)(3)n
- (5/7)(-4)n.
- Show that your formula works for a2.
a2 = (12/7)(3)2 - (5/7)(-4)2 = 4.
2. Given the recurrence ak
= 10ak - 1 - 25ak - 2,
a0 = 0, a1 = 1.
- Write out the next three terms of this
sequence.
10, 75, 500
- What is the characteristic equation?
t2 - 10t + 25 = 0
- Given the roots to the characteristic
equation both t = 5, write an equation for an
based on the linear combination of the roots to this characteristic
equation using real constants C and D.
an = C× 5n +
D× n× 5n.
- Use the initial conditions to solve
for the constants C and D and write an explicit formula for the recurrence
relation.
a0 = C(5)0
+ D(0)(5)0 = 0 ® C = 0, a1 = 0(5)1 +
D(1)(5)1 = 1 ®
D = 1/5.
an = (1/5)(n)(5)n
= n× 5n
- 1.
- Show that your formula works for a2.
a2 = 2× 52 - 1
= 2× 5 = 10.