Crosstabs, Means Tests,
and Correlation Exercises: alpha = .05 on all tests
1. Is there a relationship
between the number of police officers on staff and the type of crimes that are
most frequent?
|
1998, 5 officers |
1999, 8 officers |
Property Crime Arrests |
325 |
375 |
Violent Crime Arrests |
120 |
119 |
Analysis = Crosstabs w/
chi-square
Ho: There is no relationship between the
number of officers and the number of property or violent crime
arrests. (chi square = 0).
H1: There is a relationship
between the number of officers and the number of property or violent crime
arrests. (chi square not equal to
0).
Df = 1*1 = 1
X crit = 3.84
Expected Values
|
1998, 5 officers |
1999, 8 officers |
Totals |
Property Crime Arrests |
331.74 |
368.26 |
700 |
Violent Crime Arrests |
113.26 |
125.74 |
235 |
Totals |
445 |
494 |
939 |
Calculation of chi-square
f(o) |
f(e) |
fo-fe |
(fo-fe) (fo-fe) |
[(fo-fe) (fo-fe)]/fe |
325 |
331.74 |
-6.74 |
45.43 |
.14 |
120 |
113.26 |
6.74 |
45.43 |
.40 |
375 |
368.26 |
6.74 |
45.43 |
.12 |
119 |
125.74 |
-6.74 |
45.43 |
.36 |
|
|
|
Sum |
1.02 |
Chi-square = 1.02
Accept null.
To interpret what this
means, you need to consult the observed table again, and look at the percentage
responses (which you may need to calculate).
|
1998, 5 officers |
1999, 8 officers |
Totals |
Property Crime Arrests |
325 (73%) |
375 (76%) |
700 |
Violent Crime Arrests |
120 (27%) |
119 (24%) |
235 |
Totals |
445 |
494 |
939 |
Interpretation: There
is no relationship between the # of officers and the number of property or
violent crime arrests. Similar percentages of property crime arrests and
violent crime arrests occurred in 1998 when there were 5 officers as in 1999
when there were 8 officers.
2. Is there a relationship between race and attitude
about whether whites were hurt by affirmative action? Be sure to use the statistics that are
provided in the information below.
Number of Whites = 2238
Number of Blacks = 432
% White who think it is very likely or
somewhat likely that whites were hurt by affirmative action: 75.8%
% Black who think it is very likely or somewhat likely that whites were hurt by
affirmative action: 50.4%
p = .000, chi-square = 171.47
Analysis = Crosstabs w/ chi-square
Ho: There is no relationship between race
and and attitudes about whether whites were hurt by affirmation action (chi
square = 0).
H1: There is a relationship between race and
attitudes about whether whites were hurt by affirmation action (chi square ≠
0).
Compare p to alpha. p is less than
alpha. Reject null.
To interpret what this
means, you need to consult the observed table again, and look at the percentage
responses (which you may need to calculate).
Intepretation: There is a relationship
between race and attitude about whether whites were hurt by affirmative action
(chi-square = 37.31, p<.000). More whites (75.8%) than blacks (50.4%)
think it is very likely or somewhat likely that whites were hurt by affirmative
action.
3. I think being a feminist or not influences whether people
think homosexuals should be able to teach in public schools. Use the data below, from the GSS96, to test
my hypothesis.
|
Identify as a Feminist |
|
|
Allow Homosexuals to
Teach? |
Yes |
No |
Totals |
Yes |
156 |
508 |
664 |
No |
33 |
172 |
205 |
Totals |
189 |
680 |
869 |
Chi-square = 5.04, p = .025
Analysis = Crosstabs w/
chi-square
Ho: Being a feminist does
not influence beliefs on whether homosexuals should be able to teach school.
(chi square = 0).
H1: Being a feminist influences beliefs on whether homosexuals should be able to teach school. (chi square ≠ 0).
Compare p to
alpha. P is less than alpha. Reject null.
To interpret what this
means, you need to consult the observed table again, and look at the percentage
responses (which you may need to calculate).
|
Identify as a Feminist |
|
|
Allow Homosexuals to
Teach? |
Yes |
No |
Totals |
Yes |
156 (83%) |
508 (75%) |
664 |
No |
33 (17%) |
172 (25%) |
205 |
Totals |
189 |
680 |
869 |
Interpretation: Being a feminist influences
beliefs on whether homosexuals should be able to teach school. Feminists are more
likely to think that homosexuals should be allowed to teach school (83%) than
people who are not feminist (75%).
4. I think being a feminist
or not influences whether people think racists should be able to teach in
public schools. Use the data below, from
the GSS96, to test my hypothesis.
|
Identify as a Feminist |
|
|
Allow Racists to Teach? |
Yes |
No |
Totals |
Yes |
104 |
306 |
410 |
No |
82 |
363 |
445 |
Totals |
186 |
669 |
855 |
Chi-square = 6.04, p = .014
Analysis = Crosstab w/ chi square
Ho: Being a feminist does not influence beliefs on whether racists should be able to teach school. (chi square = 0).
H1: Being a feminist influences beliefs on whether racists should be able to teach school. (chi square ≠ 0).
compare p to alpha. P
is less than alpha. Reject null.
To interpret what this
means, you need to consult the observed table again, and look at the percentage
responses (which you may need to calculate).
|
Identify as a Feminist |
|
|
Allow Racists to Teach? |
Yes |
No |
Totals |
Yes |
104 (56%) |
306 (46%) |
410 |
No |
82 (44%) |
363 (54%) |
445 |
Totals |
186 |
669 |
855 |
Intepretation: Being a feminist influences beliefs on whether racists should be able to teach school. Feminists are more likely to think that racists should be allowed to teach school (56%) than people who are not feminist (46%).
5. I think that people with
a college degree tend to have fewer children than people without a college
degree. Use the data below, from the
GSS96, to test my hypothesis.
People with a college degree: n =
694, mean # of children = 1.41, s = 1.5
People without a college degree: n =
2188, mean # of children = 1.97, s = 1.71
Analysis = Two Group Means Test
Ho: The average number of
children among people with a college degree is greater than or equal to the
average number of children among people without a college degree. (mean 1 ≥
mean 2).
H1: The average number of
children among people with a college degree is less than the average number of
children among people without a college degree (mean 1 < mean 2).
df = 694 + 2188 –2 = use df at infinity: t
crit = 1.64
Draw diagram.
See board.
T calc = -9.33
Numerator = 1.41 – 1.97 = -.56
Denominator = sq rt of [(1.52/694)
+ (1.712/2188)] = sq rt of
.003 + .001
= -.56/.06 = -9.33
t calc is greater than t crit. Reject null.
Intepretation: People with a college degree tend to have fewer children (avg = 1.41) )than people without a college degree (avg = 1.97).
6. I think people who hold
progressive beliefs and values concerning gender differ in their amount of
happiness (on a scale that ranges from 0-7) from other Americans. Use the data below, from the GSS96, to test
my hypothesis.
People who hold progressive gender
beliefs and values: n = 672, mean happiness = 5.13, s = 2.11
Mean happiness score of all
Americans: 5.27
t calc = -1.69, p = .09
Analysis = One Group Means Test
Ho: People with progressive beliefs about gender have the same level of happiness as all Americans. (mean = 5.27)
H1:
People with progressive beliefs about gender have a different level of
happiness as all Americans. (mean ≠
5.27)
Compare p to alpha. No
calculations necessary. p is bigger than
alpha. Accept null.
Interpretation: People with
progressive beliefs about gender have the same level of happiness as all Americans.
7.
I think that
romantic partners often have different levels of satisfaction with their
relationship. I collect a sample of 9
romantic partners and ask each partner how satisfied they are with their
relationship (on a scale of 0-10). Use
the data below to test my hypothesis.
Partner 1 Satisfaction |
Partner 2 Satisfaction |
Difference |
8 |
5 |
3 |
7 |
2 |
5 |
8 |
8 |
0 |
7 |
7 |
0 |
10 |
9 |
1 |
5 |
4 |
1 |
2 |
4 |
-2 |
7 |
7 |
0 |
5 |
6 |
-1 |
Mean difference = .78, standard deviation of the difference = 1.99
Analysis = Matched Group Means Test
Ho: Romantic partners have the same level of satisfaction with their relationships (d = 0).
H1: Romantic partners do not have
the same level of satisfaction with their relationships (d ≠ 0).
Two tailed test. t crit = 2.31 (+/-) (df = 9-1)
t calc = 1.18
t = .78 / (1.99/sq rt of 9)
t = .78/(1.99/3)
t=.78/.66
t =1.18
t calc is less than t crit.
Accept null.
Interpretation: Romantic partners have the same level of satisfaction with their relationships.
7.
I think that education influences income. Use the data below
to test my hypothesis.
Group |
Sample Size |
Mean Income |
Std. Dev. |
Less than H.S. degree |
30 |
15,545 |
165.21 |
H.S. Degree |
120 |
19,621 |
342.87 |
Some College |
40 |
20,210 |
155.99 |
Bachelor’s Degree |
80 |
24,398 |
899.34 |
Graduate Degree |
15 |
33,568 |
8003.84 |
F= 14.27, p=.000
Analysis = multiple group means test (ANOVA)
Ho: There is no relationship between education and
income. Mean1= mean 2 = mean3 = mean4 =
mean5, f=0
(or you could say, education does not influence
income)
H1: There is a relationship between education and income. Mean1 ≠ mean 2 ≠
mean3 ≠ mean4 ≠ mean5, f ≠ 0
(or you could say, education does influence income)
p is less than alpha.
Reject the null.
Interpretation: Education does influence
income. As education increases, people tend to earn more income. People with a graduate degree, on average,
have the highest income ($33,568), and people with less than a high school
degree, on average, have the lowest income ($15,545).
8. Is there a relationship between SEI and number of
hours worked last week?
r = .23, p = .09 (two tailed)
analysis = correlation
Ho: There is no relationship between SEI and the
number of hours worked. r=0
H1: There is a relationship between SEI and the number of hours worked. r≠0
p is higher than alpha. Accept the null.
Interpretation: There is no linear relationship
between SEI and the number of hours that people work.
What if this had been a one tailed
test? What if you hypothesized a
positive correlation?
Ho: There is either no relationship between SEI and
the number of hours worked or a negative relationship ( r=0 or r<0)
H1: As the number of hours worked increases, SEI increases ( r > 0).
All error goes on the right hand side
of your sampling distribution.
Divide p from above in half (p = .045)
P is less than alpha. Reject null.
r*r = .23 *.23 = .05
Interpretation: There is a moderate,
positive correlation between hours worked and SEI. As the number of hours worked increases, SEI
increases. The number of hours worked
explains 5% of the variation in SEI.
10. Is there a relationship between years of education
and dollars earned?
r = .33, p = .000 (two tailed)
analysis = correlation
Ho: There is no relationship between years of
education and dollars earned. r=0
H1: There is a relationship between years of education and dollars earned. r≠0
p is lower than alpha. Reject the null.
r2 = .1089
Interpretation: There is a moderate positive
relationship between SEI and the number of hours that people work. As education increases, people’s income tends
to increase. Education explains 10.89% of
the variation in income.