Possibility Trees and the
Multiplication Rule: Permutations
Given the set {a, b, c}, there are six ways to select
two letters from the set and write them in order.
ab
ac ba bc ca cb
Each such ordering of two elements of {a, b, c} is
called a 2-permutation of {a, b, c}.
Definition: An r-permutation of a set of n
elements is an ordered selection of r elements taken from the set of n
elements. The number of r-permutations of a set of n elements is
denoted P(n, r).
Theorem 6.2.3 If n and r are integers and 1 £ r £
n, then the number of r-permutations of a set of n
elements is given by the formula
P(n,
r) = n(n – 1)(n – 2)…(n – r + 1)
or, equivalently,
P(n,
r) = n!/(n – r )!.
Exercise 16, page 293. 
- How many different PINs are represented by the same sequence of keys as
2133?
- How many different PINs are represented by the same sequence of keys as
6809?
- At an automatic teller
machine, each PIN corresponds to a four-digit numeric sequence. How many
such numeric sequences contain no repeated digit?
- Consider the set {0, 1, 2, 3,
4, 5, 6, 7, 8, 9}, how many 4-permutations are there?
- What is the probability that
a randomly chosen PIN will not have a repeated digit?
Solution
- Step one: choose one of 4,
{2, A, B, C}. Step two: choose one of 3, {1, Q, Z}. Step three: choose one
of 4, {3, D, E, F}. Step four: chose one of 4, {3, D, E, F} (although we
have already used a 3 in step 3, this is only one of the four choices and
the original number 2133 has to be counted.) So by the multiplication rule
there are 4(3)(4)(4) = 192 different PINs represented by the sequence 2133.
- Step one: choose one of 4.
Step two: choose one of 4. Step three: choose one of 1. Step four: chose
one of 4. So by the multiplication rule there are 4(4)(1)(4)
= 64 different PINs keyed by the sequence 6809.
- Consider the four step
process: 10(9)(8)(7) = 5040 PINs
with no repeated digit.
- P(10,
4) = 10! / (10 – 4)! = 10! / 6! = 10(9)(8)(7) =
5040.
- P(E) = |E|
/ |S| = 5040 / 104 = 50.4%
Some
additional links:
http://regentsprep.org/Regents/math/permut/Lperm.htm
http://regentsprep.org/Regents/math/permut/LpermRep.htm
