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For all their value, the stationary states of
quantum mechanics are anathema to our everyday
experience, and often present conceptual blocks
to our understanding. The fullest appreciation of
quantum ideas comes ultimately by examining the
behavior of wave packets. A wave packet
refers to a waveform that is concentrated in
some well-defined region of space. In this way we
can approximate in quantum terms the
localization expected of a classical
particle: according to the Born interpretation, a
highly-concentrated wavefunction (read
wave packet) is one for which the particle
can be found with appreciable probability only in
a very small region.
Free particles are those subject to no force.
For a free particle, the potential energy is
everywhere constant and may be taken as zero. Even so, with few exceptions
the task of solving the Schrödinger wave
equation for the time development of any initial
wave packet is formidable. By
contrast, numerical simulation affords a
viable alternative that enables visualization of
quantum effects on an unprecedented scale.
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Owing to its relative mathematical simplicity,
the gaussian wave packet traditionally has
been a popular way to represent the initial state
of many quantum systems, though it must be
confessed that the gaussian representation is
often only an approximation to reality.
The applet below shows a gaussian waveform
used to represent a free electron that is
initially localized to a region several angstroms
(Å) in length (atomic dimensions). The
gaussian profile for the initial wavefunction is
recorded as φ(x) in the Equation View of the applet, along with the
particle mass = 511
keV/c2 which we recognize as
the mass of an electron. The packet is centered
at the coordinate origin x = 0 and w
= 1.0 Å is a measure of its width.
Indeed, w may be identified with the
(initial) uncertainty Δx in locating this
electron. ψ(x) is the result of propagating the initial wave forward in time according to the Schrödinger equation, and coincides with φ(x) at t = 0. At this instant, the graph of ψ(x) is
shown on the Graphics: [x] tab; here we
can visually confirm and measure the packet width
with the help of the Trace feature: right
click on the graph and select Trace from
the popup menu, then determine the extent of the
wave packet by subtracting the coordinates of
some identical feature on either side of the
central peak. The assignment of width is somewhat
arbitrary, since the wave never truly falls
to zero. The important point is that
using any sensible definition, the packet
width is proportional to w. For |x|
= w, the wave has fallen
to exp(–1/4) =
0.7788... of its peak value.
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Next observe the evolution of this wave packet
by clicking the Play button on the bottom panel of
the applet. Complete control over the
developing waveform is afforded by the remaining
buttons on the panel: Stop , Reverse , Restart , Step Ahead , and Step
Back .
[Also, right-clicking on the panel allows for
adjusting the frame rate, the number of
'clock ticks' between screen redraws, and the
elapsed time between 'ticks'; all affect the
speed of animation and can be tweaked (the first
two with the 'clock' running) to achieve the most
pleasing visual effect.]
The waveform steadily spreads (disperses) while
the peak remains fixed in place. The changing
colors signal a complex-valued wavefunction.
The phase of a complex number (the function
value) is represented here by color which, like
phase angle, repeats with a definite period. [The
'colorwheel' follows the rainbow from red to
green to violet, then back to red again through
magenta.] The theory for this case shows
that the wave profile remains gaussian but
acquires a [space-varying] phase and an
ever-increasing width. As the packet spreads, the
peak height diminishes so as to conserve total
probability. Note that the waveform
continues to spread well beyond the field of
view: QMTools is able to simulate an infinite
domain by applying transparent boundary
conditions at the endpoints of a finite interval
[see Am. J. Phys. 72, 351
(2004)]. Time is measured here in
femtoseconds (fs); 1 fs = 10–15 s. Use
the applet to estimate how long it
takes for the initial waveform to spread
uniformly throughout the entire visible
range (extending from –10 Å to +10 Å). What
are the consequences of this result in terms of
locating the electron?
Besides dispersing, a free-particle wave
packet also translates with a speed equal to
the group velocity of its de Broglie wave
consituents. Since the waveform in the
preceding applet remains centered at the origin,
it cannot describe an electron with a nonzero
(average) velocity. The applet below remedies
this deficiency by assigning the initial wave
with an overall multiplier of the form
exp(iax), having real and imaginary
parts cos(ax) and sin(ax),
respectively. The speed of this packet is
proportional to the wavenumber a (= 0.5
Å–1); in fact, the average momentum of
the electron described by this packet can be
shown to be <p> = ћa = (1.973
keV·Å/c)(0.5 Å–1) = 0.9865
keV/c. With the extra phase factor
for nonzero momentum, the initial wave is
already complex-valued, hence the colorful
display below even at time t = 0.
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Once again observe the evolution of this
wave packet by clicking the Play button on the bottom panel of
the applet. Use the Trace feature to track
the displacement of the peak and determine how
fast it moves; this is the group velocity
of the packet. A classical electron with
momentum 0.9865 keV/c would have
velocity (0.9865 keV/c/511
keV/c2) = 1.93 ×
10–3c = 5.79 Å/fs. How does
this figure compare with the measured group
velocity in this case?
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A wave packet with even a modest degree
of localization Δx is made up of many de
Broglie waves taken from a relatively broad range
of wavenumbers Δk. Constructing a wave
packet from individual de Broglie waves is
an instance of a technique known to
mathematicians as Fourier transformation. The
Fourier transform superposes (adds)
individual plane waves of the form
exp(ikx) with differing wavenumbers
k and amplitudes g(k)
to form a new function f(x). The
profile f(x) is fixed by the
choice of mixing coefficients g(k).
In mathematical parlance, f(x) and g(k) constitute a Fourier transform
pair, each one being the Fourier transform of the
other. The theory of the Fourier transform
shows that the widths of a function and its
Fourier transform are inversely related, i.e.,
if Δx is the width
of
f(x)
and Δk is the width
of g(k),
then Δx·Δk
~ 1. The applet
below can be used to confirm this reciprocal
relationship for the case of a gaussian waveform.
The graph on the Graphics: [x] tab
shows the initial wavefunction whose functional
form appears in the Equation View
as ψ(x); it is again a gaussian
multiplied by exp(iax) and centered at
x = 0, but now with reduced width w
= 0.5 Å. The Fourier transform
of ψ(x) is displayed on the current
tab, labeled Graphics: [k], and in designated in the Equation View as ψ~(k). The
appearance of the transform is unmistakably
similar to the original
function ψ(x); in fact, the Fourier
transform of a gaussian is another gaussian! The
wavefunction and its Fourier transform can be viewed simultaneously as follows: from the
Graphics: [x]
tab, right click anywhere in the graph and select "Display in
Window" from the popup menu. Reposition | resize the new window as
desired. Repeat the procedure from the Graphics: [k] tab to
create a second window for the transform function. Both the function
and its transform are now visible, with the axis labels clearly
distinguishing the two members of this transform pair.
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Now lets change the width of ψ(x)
to see what effect this has on its
Fourier transform. Switch over to Equation View and right click on the entry for w, then select "Edit parameter..." from the popup menu.
Use the slider to set
different values for the width (Δx)
of ψ(x), and observe the effect on
the width (Δk) of its transform. [The slider affects only the
highlighted digits; the
first digit highlighted can be moved left (right) using the up
(down) arrows to the right of this field. Extra digits can be added
before or after the decimal by typing directly in the text field.] Interpret
your observations in terms of the reciprocity of
the Fourier transform. The momentum of an
individual de Broglie wave is p = ћk; it
follows that a spread in wavenumbers
Δk translates into an
uncertainty in particle momentum Δp
= ћΔk. In this way the
reciprocity of the Fourier transform
(Δx·Δk
~ 1) leads directly to the
position-momentum Uncertainty Principle
discovered by Heisenberg,
Δx·Δp ~
ћ. The wavenumber a
of the original wave packet also can be adjusted
using the same technique used to change the
width. Try different values for a to see
its effect on the wavefunction and its Fourier
transform.
Finally, restore the original wavenumber
(a = 0.5 Å–1) and width
(w = 0.5 Å) and observe the evolution of
the Fourier transformed wave (click the Play
button ).
How would you describe the short-term result?
[The 'spiking' evident for t > 0.2 fs
is an artifact: the Fourier transformation
effectively 'clips' the coordinate
wavefunction to the visible field, when in fact
the transparent boundary conditions show it
quickly spreads well beyond the interval limits.]
Quantum theory holds that the Fourier
transformed wavefunction gives probability
amplitudes for momentum in the same way that the
Schrodinger wavefunction prescribes probabilities
for position. Interpret the short-term
evolution in that light.
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Gaussian wavefunctions lend themselves to
studies of wave propagation because of their
appealing mathematical properties, but do those
special features skew our results? To put it
another way, do the general conclusions
reached above for a gaussian wave packet
remain valid even for non-gaussian packets? To
explore this question, the applet below
prescribes an initial wave having
a non-gaussian profile. As before, the formula for
this new profile appears in the Equation View as φ(x), ψ(x) is the result of propagating the wave forward in time, and the
waveform itself is plotted at t = 0 on the Graphics:
[x] tab. Like its gaussian predecessor,
this initial wave exhibits a single peak at
x = 0, has wavenumber a = 0.5
Å–1 and width w = 0.5 Å. But
the similarities end there; the shape is
noticeably different and the peak, especially, is
'flattened'. Furthermore, the Fourier transform
of ψ(x), displayed on
the Graphics: [k] tab, is
decidedly unlike the original wave.
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Follow the preceding instructions to display the wavefunction
and its Fourier transform in separate windows for easy comparison. Check the reciprocity rule for this case by
changing the width of the initial wave
while observing its Fourier transform. Is
reciprocity valid for this transform pair? Also
examine the propagation of the new waveform. Do
you see any significant differences between this
evolution and gaussian evolution?
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